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20 September, 03:32

A gas has a volume of 10 L at 0 C what is the final temperature of the gas if it volume increases to 25L

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  1. 20 September, 05:05
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    Answer: 682.5K

    Explanation:

    Initial volume of gas V1 = 10L

    Initial temperature T1 = 0°C

    Convert temperature in Celsius to Kelvin

    (0°C + 273°C = 273K)

    Final temperature T2 = ?

    Final volume V2 = 25L

    According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

    Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

    10L/273 = 25L/T2

    To get the value of T2, cross multiply

    10L x T2 = 273 x 25

    10L x T2 = 6825 L

    T2 = (6825L/10L)

    T2 = 682.5K

    Thus, the new temperature of the gas is 682.5K
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