A gas has a volume of 10 L at 0 C what is the final temperature of the gas if it volume increases to 25L

Answer: 682.5K

Explanation:

Initial volume of gas V1 = 10L

Initial temperature T1 = 0°C

Convert temperature in Celsius to Kelvin

(0°C + 273°C = 273K)

Final temperature T2 = ?

Final volume V2 = 25L

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

10L/273 = 25L/T2

To get the value of T2, cross multiply

10L x T2 = 273 x 25

10L x T2 = 6825 L

T2 = (6825L/10L)

T2 = 682.5K

Thus, the new temperature of the gas is 682.5K