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14 September, 02:05

Calculate the percent yield of benzyl alcohol Sue obtained when doing the following reaction. Sue started with 2.1 g of benzoic anhydride and 0.15 g of sodium borohydride (NaBH4). She obtained 0.5 g of benzyl alcohol. You must show all of your work to receive any credit.

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  1. 14 September, 03:10
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    The percent yield is 116.6 %

    Explanation:

    Step 1: Data given

    Mass of benzoic anhydride = 2.1 grams

    Mass of sodium borohydride = 0.15 grams

    Molar mass of benzoic anhydride = 226.23 g/mol

    Molar mass of NaBH4 = 37.83 g/mol

    Mass of benzyl alcohol produced = 0.5 grams

    Step 2: The balanced equation

    C14H10O3 + NaBH4 → C7H6O2 + C7H8O + NaB

    Step 3: Calculate moles of C14H10O3

    Moles C14H10O3 = Mass / molar mass

    Moles C14H10O3 = 2.10 grams / 226.23 g/mol

    Moles C14H10O3 = 0.00928 moles

    Step 4: Calculate moles NaBH4

    Moles NaBH4 = 0.150 grams / 37.83 g/mol

    Moles NaBH4 = 0.00397 moles

    Step 5: Calculate limiting reactant

    For 1 mol of C14H10O3 we need 1 mol of NaBH4 to produce 1 mol of C7H8O

    NaBH4 is the limiting reactant. It will completely be consumed (0.00397 moles).

    C14H10O3 is in excess. There will react 0.00397 moles.

    There will remain 0.00928 - 0.00397 = 0.00531 moles

    Step 6: Calculate moles of C7H8O

    For 1 mol of C14H10O3 we need 1 mol of NaBH4 to produce 1 mol of C7H8O

    For 0.00397 of C14H10O3 we need 0.00397 mol of NaBH4 to produce 0.00397 mol of C7H8O

    Step 7: Calculate mass of C7H8O

    Mass of C7H8O = Moles * molar mass

    Mass of C7H8O = 0.00397 moles * 108.14 g/mol

    Mass of C7H8O = 0.429 grams = theoretical yield

    Step 8: Calculate % yield

    % yield = (actual yield / theoretical yield) * 100%

    % yield = 0.5/0.429) * 100 %

    % yield = 116.6 %

    The percent yield is 116.6 %
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