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26 September, 20:44

500. mL of gas is contained at STP. The volume changes to 560 mL at 20.°C

What is the pressure (in atm) ?

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  1. 26 September, 22:09
    0
    P₂ = 0.96 atm

    Explanation:

    Given dа ta:

    Initial volume = 500 mL

    Initial pressure = 1 atm

    Initial temperature = 273 K

    Final volume = 560 mL

    Final temperature = 20°C (20 + 273 = 293K)

    Final pressure = ?

    Formula:

    P₁V₁/T₁ = P₂V₂/T₂

    P₁ = Initial pressure

    V₁ = Initial volume

    T₁ = Initial temperature

    P₂ = Final pressure

    V₂ = Final volume

    T₂ = Final temperature

    Solution:

    According to general gas equation:

    P₁V₁/T₁ = P₂V₂/T₂

    P₂ = P₁V₁ T₂ / T₁ V₂

    P₂ = 1 atm * 500 mL * 293 K / 273 K * 560 mL

    P₂ = 146500 atm. mL. K / 152880 k. mL

    P₂ = 0.96 atm
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