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18 May, 22:28

I2 is produced by the reaction of 0.4235 mol of CuCl2 according to the following equation: 2CuCl2+4KI 2CuI+4KCl+I2

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  1. 19 May, 02:15
    0
    React with 0.847 mol of KI

    Produce:

    0.4235 mol of CuI

    0.847 mol of KCl

    0.21175 moles de I2

    Explanation:

    2CuCl2 + 4KI produce 2CuI + 4KCl + I2

    The stoichiometric coefficients give us the relationship in moles:

    2 mol of CuCl2 ... react whit ... 4 mol of KI

    0.4235 mol of CuCl2 ... react whit ... X = 0.847mol of KI

    2 mol of CuCl2 ... produce ... 2 mol of CuI

    0.4235 mol of CuCl2 ... produce ... X=0.4235 mol of CuI

    2 mol of CuCl2 ... produce ... 4 mol of KCl

    0.4235 mol of CuCl2 ... produce ... X = 0.847 mol of KCl

    2 mol of CuCl2 ... produce ... 1 mol of I2

    0.4235 mol of CuCl2 ... produce ... X = 0.21175 moles de I2

    If you need to know the mass that is produced you just have to multiply the moles by the molecular mass
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