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27 August, 19:11

For a certain experiment, a student requires 100 milliliters of a solution that is 8% HCl (hydrochloric acid). The storeroom has only solutions that are 5% HCl and 15% HCl. How many milliliters of each available solution should be mixed to get 100 milliliters of 8% HCl?

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  1. 27 August, 20:07
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    70 mL of 5% HCl and 30 mL of 15% HCl

    Explanation:

    We will designate x to be the fraction of the final solution that is composed of 5% HCl, and y to be the fraction of the final solution that is composed of 15% HCl. Since the percentage of the final solution is 8%, we can write the following expression:

    5x + 15y = 8

    Since x and y are fractions of a total, they must equal one:

    x + y = 1

    This is a system of two equations with two unknowns. We will proceed to solve for x. First, an expression for y is found:

    y = 1 - x

    This expression is substituted into the first equation and we solve for x.

    5x + 15 (1 - x) = 8

    5x + 15 - 15x = 8

    -10x = - 7

    x = 7/10 = 0.7

    We then calculate the value of y:

    y = 1 - x = 1 - 0.7 = 0.3

    Thus 0.7 of the 100 mL will be the 5% HCl solution, so the volume of 5% HCl we need is:

    (100 mL) (0.7) = 70 mL

    Similarly, the volume of 15% HCl we need is:

    (100 mL) (0.3) = 30 mL
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