Does 1 gram of phosphorus react with 6 grams of iodine to form 4 grams of phosphorus triodine in P4 (s) + 6I2 (s) = 4PI3 (s)

No

Explanation:

One mole of P₄ react with six moles of I₂ and gives 4 moles of PI₃.

When one gram phosphorus and 6 gram of iodine react they gives 8.234 g ram of PI₃.

Given dа ta:

Mass of phosphorus = 1 g

Mass of iodine = 6 g

Mass of PI₃ = ?

Solution:

Chemical equation:

P₄ + 6I₂ → 4PI₃

Number of moles of P₄:

Number of moles = Mass / molar mass

Number of mole = 1 g / 123.9 g/mol

Number of moles = 0.01 mol

Number of moles of I₂:

Number of moles = Mass / molar mass

Number of moles = 6 g / 253.8 g/mol

Number of moles = 0.024 mol

Now we will compare the moles of PI₃ with I₂ and P₄.

I₂ : PI₃

6 : 4

0.024 : 4/6*0.024 = 0.02

P₄ : PI₃

1 : 4

0.01 : 4 * 0.01 = 0.04 mol

The number of moles of PI₃ produced by I₂ are less it will be limiting reactant.

Mass of PI₃ = moles * molar mass

Mass of PI₃ = 0.02 mol * 411.7 g/mol

Mass of PI₃ = 8.234 g