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21 January, 17:54

If 10.0 liters of h2 (g) at STP is heated to a temperature of 546 K, pressure remaining constant, the new volume of the gas will be

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  1. 21 January, 19:41
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    20L

    Explanation:

    The following data were obtained from the question:

    Initial volume (V1) = 10L

    Initial Temperature (T1) = stp = 273K

    Final temperature (T2) = 546K

    Final volume (V2) = ... ?

    The new volume of the gas can be obtained by using the Charles' law equation as shown below:

    V1/T1 = V2/T2

    10/273 = V2/546

    Cross multiply to express in linear form

    273 x V2 = 10 x 546

    Divide both side by 273

    V2 = (10 x 546) / 273

    V2 = 20L

    Therefore, the new volume of the gas is 20L.
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