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14 March, 14:19

Donald needs to produce 5000 milliliters of 32% alcohol solution. At his disposal he has 40% alcohol solution and 20% alcohol solution. How much of each does he need in order to produce his desired solution?

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  1. 14 March, 17:00
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    The answer to your question is 3 L of solution 40% and 2 L of solution 20%

    Explanation:

    Data

    Final volume = Vf = 5000 ml = 5 L

    Final concentration = Cf = 32%

    Concentration 1 = C1 = 40%

    Concentration 2 = C2 = 20%

    Volume 1 = x

    Volume 2 = 5 - x

    Process

    1. - Write an equation to solve this problem

    VfCf = C1V1 + C2V2

    2. - Substitution

    32 (5) = 40x + 20 (5 - x)

    3. - Solve for x

    160 = 40x + 100 - 20x

    160 - 100 = 40x - 20x

    60 = 20x

    60/20 = x

    x = 3

    Then, Volume 1 = 3 L

    4. - Find Volume 2

    Volume 2 = 5 - 3

    Volume 2 = 2 L
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