Ask Question
14 March, 11:26

in a certain solvent is first order with respect to (CH3) 3CBr and zero order with respect to OH2. In several experiments the rate constant k was determined at different temperatures. A plot of ln (k) versus 1/T was constructed that resulted in a straight line with a slope of 21.10 3 104 K and a y intercept of 33.5. Assume that k has units of s21. a. Determine the activation energy for this reaction. b. Determine the value of the frequency factor A. c. Calculate the value of k at 258C.

+1
Answers (1)
  1. 14 March, 13:54
    0
    Ea = - 175.45J

    A = 3.5*10^14

    k=3.64 * 10^14 s^2.

    Explanation:

    From

    ln k = - (Ea/R) (1/T) + ln A

    This is similar to the equation of a straight line:

    y = mx + c

    Where m = - (Ea/R)

    c = ln A

    y = ln k

    a)

    Therefore

    21.10 3 104 = - (Ea/8.314)

    Ea = - (21.10 3 104*8.314)

    Ea = - 175.45J

    b) ln A = 33.5

    A = e^33.5

    A = 3.5*10^14

    c)

    k = Ae^-Ea/RT

    k = 3.5*10^14 * e^ - (-175.45/8.314*531)

    k = 3.64 * 10^14 s^2.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “in a certain solvent is first order with respect to (CH3) 3CBr and zero order with respect to OH2. In several experiments the rate constant ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers