A red blood cell is placed into each of the following solutions. Indicate whether crenation, hemolysis, or neither will occur. Solution A: 2.57 % (m/v) NaCl Solution B: 3.78 % (m/v) glucose Solution C: distilled H2O Solution D: 6.15 % (m/v) glucose Solution E: 5.0% (m/v) glucose and 0.9% (m/v) NaCl

Question

Chemistry

Asher Reese

21 July, 23:59

A red blood cell is placed into each of the following solutions. Indicate whether crenation, hemolysis, or neither will occur. Solution A: 2.57 % (m/v) NaCl Solution B: 3.78 % (m/v) glucose Solution C: distilled H2O Solution D: 6.15 % (m/v) glucose Solution E: 5.0% (m/v) glucose and 0.9% (m/v) NaCl

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Charlotte · Answer 1

Solution A: crenation

Solution B: hemolysis

Solution C: hemolysis

Solution D: crenation

Solution E: crenation

Explanation:

Hemolysis is the rupturing of red blood cells, which results in the release of hemoglobin (from within the red blood cells) into the plasma. If a red blood cell is placed in a hypotonic solution, water will flow into the cell, the cell will swell and hemolysis will.

Crenation: when a red blood cell is placed in a hypertonic solution (such as highly saline solution), the red blood cell will lose water (osmosis) and will shrink in size. The red blood cell has undergone crenation.

In order for a red blood cell to prevent from undergoing hemolysis or crenation, the cell must be placed in an isotonic solution, i. e either in 0.9% (m/v) NaCl solution or 5% glucose solution

Solution B and Solution C are hypotonic solution, thus red blood cell has undergone hemolysis. Solution A, D and E are hypertonic solution. thus red blood cell has undergone crenation