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15 December, 23:30

12. Calculate the volume of a 0.45M solution containing 20 g of NaOH.

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Answers (2)
  1. 16 December, 00:08
    0
    1.11L

    Explanation:

    Firstly calculate the molar mass of NaOH, 40+16+1=40g/mol

    Number of moles = molarity*volume

    Number of moles=mass given/molar mass

    Mass given=20g

    Molar mass=40

    Number of moles=20/40=0.5moles

    Molarity=0.45M

    Volume=number of moles/molarity

    Volume=0.5/0.45

    Volume=1.11L
  2. 16 December, 01:00
    0
    1.11L

    Explanation:

    To solve this problem, first, let us calculate the number of mole of NaOH as shown below:

    Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol

    Mass of NaOH = 20g

    Number of mole = ?

    Number of mole = Mass / Molar Mass

    Number of mole of NaOH = 20/40 = 0.5mol

    Now we can calculate the volume of the solution as follows:

    Molarity = 0.45M

    Mole = 0.5mole

    Volume = ?

    Molarity = mole / Volume

    Volume = mole / Molarity

    Volume = 0.5/0.45

    Volume = 1.11L
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