The volume of a weather balloon is 200.0 L and its internal pressure is 1.17 atm when it is launched at 20 °C. The balloon rises to an altitude in the stratosphere where its internal pressure is 63 mmHg and the temperature is 210 K. What is the volume (in L) of the balloon then?

2022 L

Explanation:

Ideal gas laws will work for gas in the balloon

The general gas law is for a gas at two arbitrary states 1 and 2 is given by

(P₁ V₁) / T₁ = (P₂ V₂) / T₂

P₁ = 1.17 atm

V₁ = 200.0 L

T₁ = 20°C = 293.15 K

P₂ = 63 mmHg = 0.0829 atm

V₂ = ?

T₂ = 210 K

(1.17 * 200) / 293.15 = (0.0829 * V₂) / 210

V₂ = (210 * 1.17 * 200) / (293.15 * 0.0829)

V₂ = 2022 L