A solution was prepared by dissolving 0.05000 mol of sucrose in 100.0 kg of water. Find

the molality of the solution.

0.0005mol/kg

Explanation:

Molality = mole of solute/mass of solvent (kg)

From the question, we obtained the following dа ta:

Mole of solute = 0.05mole

Mass of solvent = 100kg

Molality = 0.05/100

Molality = 0.0005mol/kg

The molality of the solution is 0.0005mol/kg

Answer: 5x10-4 mole / kg

Explanation: Molality is expressed as number of moles per unit kilograms of solvent.

m = n / kg

= 0.05000 mole / 100.0 kg

= 0.0005 m or 5x10-4 mole / kg