suppose work input is 25 j and the output distance is 10 m factoring in the effect of friction which must be true about output force a) it equals 2.5n b) it is less than 2.5n c) it is greater than 2.5n

Therefore F ∠ 2.5N

Explanation:

Definition of Work:

It is the amount of energy transferred.

Mathematical expression:

W = F * d

By taking the friction into count it will define as:

Input work = work against friction * output work

No we will put the values:

25 J = w + 10 m

j = kg m²/s²

25 kg m²/s² = w + 10 m

when friction is exist then w > 0

25 kg m²/s² - 10 m > 0

15 N > 0

Therefore F ∠ 2.5N