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14 July, 07:16

A compound has an empirical formula of CHBr2. If it's molar mass is 345.6 grams, what is it's molecular formula

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  1. 14 July, 09:22
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    The molecular formula is C2H2Br4

    Explanation:

    Molar Mass of CHBr2 = 12 + 1 + (2x80) = 12 + 1 + 160 = 173

    The molecular formula = n x empirical formula

    Molar Mass of the compound = 345.6

    Empirical formula = CHBr2

    n (CHBr2) = 345.6

    n x 173 = 345.6

    n = 345.6/173 = 2

    Therefore the molecular formula is n (CHBr2) = 2 (CHBr2) = C2H2Br4
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