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2 October, 02:27

For the following reaction

2 R (g) - -> Q (g)

if the equilibrium concentration of R is 0.776 M and that of Q is 1.22 M at 25? C, what is the value of the equilibrium constant at this temperature?

a. 0.521

b. 0.494

c. 2.03

d. 1.57

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Answers (1)
  1. 2 October, 04:58
    0
    (C) 2.03

    Explanation:

    Kc (equilibrium constant) = [Q]/[R]^2

    [Q] = 1.22 M

    [R] = 0.776 M

    Kc = 1.22/0.776^2 = 1.22/0.602176 = 2.03 (to 2 decimal places)
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