Look at the chemical equation:

2H2S + 3O2 → 2H2O + 2SO2

How many atoms of hydrogen (H) are present on both sides of the equation?

A. 2

B. 3

C. 4

D. 6

C. 4

Explanation:

From the left hand (reaction) side of the equation hydrogen exist as a molecule in hydrogen sulfide (2H2S). what this simply means it contain two atoms. Now multiplying the bold number in 2H2S with 2 atoms of hydrogen which constitute a molecule. it will give 4. On the left Side hydrogen atom (2H2) is 4.

On the right (product) side where Hydrogen appear in the water molecules (2H20), multiply 2 by 2 (2H2) you will get 4 also.

so Hydrogen atom is 4 on both side of the equation.

4

Explanation:

4 atoms on each size since hydrogen exist as a molecule