The radius of a hydrogen atom is 37 pm and its mass is 1.67 * 10-24 g. What is the density of the atom in grams per cubic centimeter? Assume the atom is a sphere with:

Volume = (4/3) (3.14) (r^3)

Question

Chemistry

Amari Mccarty

24 May, 21:47

The radius of a hydrogen atom is 37 pm and its mass is 1.67 * 10-24 g. What is the density of the atom in grams per cubic centimeter? Assume the atom is a sphere with:

Volume = (4/3) (3.14) (r^3)

+3

Answers (2)

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Mclaughlin · Answer 1

V = 4/3 * 3.1416 * (37x10-10) 3

V = 2.12x10-25 cm3

d = m/V

d = 1.67x10-24 / 2.12x10-25 = 7.87 g/cm3

The difference in temperature, let's convert F to ºC:

ºC = - 80-32/1.8 = - 62.22 ºC

dT = - 92.6 + 62.2 = - 30.4 ºC

Melody · Answer 2

V = 4/3 * 3.1416 * (37x10-10) 3

V = 2.12x10-25 cm3

The radius of a hydrogen atom is 37 pm and its mass is 1.67 * 10-24 g. What is the density of the atom in grams per cubic centimeter? Assume the atom is a sphere with:Volume = (4/3) (3.14) (r^3)

The radius of a hydrogen atom is 37 pm and its mass is 1.67 * 10-24 g. What is the density of the atom in grams per cubic centimeter? Assume the atom is a sphere with:

Volume = (4/3) (3.14) (r^3)