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Yesterday, 23:01

How many grams of water will absorb a total of 2400 joules of energy when the temperature changes from 10.0°C to 30.0°C?

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  1. Today, 00:56
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    28.7 grams of water

    Explanation:

    Calorimetry problem:

    Q = C. m. ΔT

    2400 J = 4.18 J/g°C. m. (30°C - 10°C)

    2400 J = 4.18 J/g°C. m. 20°C

    2400J = 83.6 J/g. m

    2400J / 83.6 g/J = m

    28.7 g = m
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