Find the ratio of speeds of an electron and a negative hydrogen ion (one having an extra electron) accelerated through the same voltage, assuming non-relativistic final speeds. Take the mass of the hydrogen ion to be 1.67*10^{-27} kg.

42.8

Explanation:

A particle travelling through potential difference V has energy E = qV = 1/2mv²

v = √ (2qV / m)

ve = √ (2qV / me)

vh = √ (2qV / mh)

ve / vh = √ ((2qV / me) : (2qV / mh) = √ (mh / me) where mh = mass of hydrogen ion and me is mass of electron, V voltage is the same, ve is speed of electron and vh is the speed of hydrogen ion

ve / vh = √ (mh / me) = √ (1.67 * 10⁻²⁷ kg) / (9.11 * 10 ⁻³¹ kg) = 42.8