A 71.0 mL aliquot of a 1.80 M solution is diluted to a total volume of 218 mL. A 109 mL portion of that solution is diluted by adding 113 mL of water. What is the final concentration? Assume the volumes are additive

Question

Chemistry

Violet Griffin

12 February, 00:02

A 71.0 mL aliquot of a 1.80 M solution is diluted to a total volume of 218 mL. A 109 mL portion of that solution is diluted by adding 113 mL of water. What is the final concentration? Assume the volumes are additive

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Answers (1)

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Aryana Guerra · Answer 1

The final concentration is 0.288 M (approximately)

Explanation:

Using dilution formula:

C1V1 = C2V2

Where C1 is the initial concentration

C2 is the final concentration

V1 is the initial volume

V2 is the final volume

In the first dilution, C1 = 1.8M,

V1 = 71mL, V2 = 218mL from the formula C2 = 1.8 * 71/281

=0.5862M

In the second dilution,

C1 = 0.5862M, V1 = 109mL, V2 = 222 mL (109+113)

C2 = 0.5862 * 109 : 222

= 0.288 M (approximately) assuming volume is additive.