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12 February, 00:02

A 71.0 mL aliquot of a 1.80 M solution is diluted to a total volume of 218 mL. A 109 mL portion of that solution is diluted by adding 113 mL of water. What is the final concentration? Assume the volumes are additive

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  1. 12 February, 01:45
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    The final concentration is 0.288 M (approximately)

    Explanation:

    Using dilution formula:

    C1V1 = C2V2

    Where C1 is the initial concentration

    C2 is the final concentration

    V1 is the initial volume

    V2 is the final volume

    In the first dilution, C1 = 1.8M,

    V1 = 71mL, V2 = 218mL from the formula C2 = 1.8 * 71/281

    =0.5862M

    In the second dilution,

    C1 = 0.5862M, V1 = 109mL, V2 = 222 mL (109+113)

    C2 = 0.5862 * 109 : 222

    = 0.288 M (approximately) assuming volume is additive.
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