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9 December, 08:06

A researcher studying the nutritional value of a new candy places a 6.80 g 6.80 g sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.25 ∘ C. 2.25 ∘C. If the heat capacity of the calorimeter is 32.00 kJ ⋅ K - 1, 32.00 kJ⋅K-1, how many nutritional Calories are there per gram of the candy?

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  1. 9 December, 11:41
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    2523.23 cal / g

    Explanation:

    Mass = 6.80g

    Temperature increase (T2 - T1) = 2.25

    Heat capaity of calorimeter = 32.00kJK-1 = 7.64818 KcalK-1 (Converting to calories by multiplying by 4.18)

    Heat capacity = 7648.18 cal (converting to cal by mutltiplying by 1000)

    Heat capacity = Heat Supplied / Temperature rise

    Heat Supplied = Heat capacity * Temperature rise

    Heat supplied = 7648.18 * 2.25

    Heat Supplied = 17208.405 cal

    To obtain the per gram value, we divide by the mass.

    This gives us; 17208.405 / 6.80 = 2523.23 cal / g
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