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21 April, 03:17

The rate constant of a reaction is 4.50*10-5 L/mol·s at 195°C and 3.20*10-3 L/mol·s at 258°C. What is the activation energy of the reaction?

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  1. 21 April, 03:23
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    138.46KJ

    Explanation:

    In (k1/k2) = Ea/Rx (1/T1-1/T2)

    T1 = 195+273 = 468k

    T1 = 195 + 273 = 531k

    K1 = 4.5 X 10-5

    K2=3.2x10-3

    Rx = 8.3145

    In (71.111) = Ea/8.3145 (1/468 - 1/531)

    4.26409x 8.3145 = Ea (0.000256)

    Ea=138464.1

    =138.46kJ
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