C. How many grams of Na2SiO3 can react with 0.800 g of HF?

Mass = 0.610 g

Explanation:

Given dа ta:

Mass of Na₂SiO₃ = ?

Mass of HF = 0.800 g

Solution:

Chemical equation:

Na₂SiO₃ + 8HF → H₂SiF₆ + 2NaF + 3H₂O

Number of moles of HF:

Number of moles = mass / molar mass

Number of moles = 0.800 g / 20 g/mol

Number of moles = 0.04 mol

Now we will compare the moles of HF and Na₂SiO₃.

HF : Na₂SiO₃

8 : 1

0.04 : 1//8*0.04 = 0.005

Mass of Na₂SiO₃:

Mass = number of moles * molar mass

Mass = 0.005 mol * 122.07 g/mol

Mass = 0.610 g