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26 November, 13:49

The heat of combustion of butane is 2877.5 kJ/mol how much heat in calories will be produced in the combustion of 100.0 g of butane?

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  1. 26 November, 16:54
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    The answer is 1,185,000 cal or 1,185 kcal

    Explanation:

    We convert the weight of butane (C₄H₁₀, MW = 58) to mole

    n = m/M = 100.0 / 58 = 1.724 mol

    The heat of combustion of 100.0 g or 1.724 mol of butane is

    H (kJ) = 1.724 mol x 2,877.5 kJ/mol = 4,960.8 kJ

    Then we convert the unit to calories

    H (cal) = 4,960.8 kJ / 4.184 kJ/kcal = 1,185 kcal = 1,185,000 cal
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