When NaI is added to a solution of Cu (NO₃) ₂, the following reaction occurs: 2NaI (aq) → CuI₂ (s) + 2NaNO₃ (aq)
If a chemist needs to make 350.0 g of CuI₂, how many mL of a 3.3 M solution of NaI must be used? Assume that there is excess copper (II) nitrate.
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Home » Chemistry » When NaI is added to a solution of Cu (NO₃) ₂, the following reaction occurs: 2NaI (aq) → CuI₂ (s) + 2NaNO₃ (aq) If a chemist needs to make 350.0 g of CuI₂, how many mL of a 3.