the pressure on 325 ml sample of oxygen gas was determined to be 0.768 atm. what will the volume of the shape be at 1220 torr?

156 mL will be the new volume of the shape

Explanation:

First of all, we need to convert the Torr to atm.

1220 Torr. 1 atm / 760 Torr = 1.60 atm

When the temperature remains constant, it is satisfied that the volume is modified indirectly proportionally.

Pressure is increased, then volume decreases

Pressure is decreased, then volume increases

P₁. V₁ = P₂. V₂

0.768 atm. 325mL = 1.60 atm. V₂

V₂ = 0.768 atm. 325mL / 1.60 atm → 156 mL