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3 April, 22:06

What mass of carbon dioxide gas occupies a volume of 8.13 L

at 204 kPa and a temperature of 95 0 °C?

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Answers (1)
  1. 3 April, 23:51
    0
    23.76g

    Explanation:

    To solve for the mass of carbon dioxide (CO2), let us first obtain the number of mole of CO2.

    From the question, the following were obtained:

    V = 8.13L

    P = 204kPa = 204000Pa

    Recall: 101325Pa = 1atm

    204000Pa = 204000/101325 = 2atm

    T = 95°C = 95 + 273 = 368K

    R = 0.082atm. L/K/mol

    n = ?

    PV = nRT

    n = PV / RT

    n = 2 x 8.13 / 0.082 x 368

    n = 0.54mole

    Now let us convert 0.54mole of CO2 to gram. This is illustrated below:

    Molar Mass of CO2 = 12 + (16x2) = 12 + 32 = 44g/mol

    Number of mole of CO2 = 0.54mole

    Mass of CO2 = ?

    Number of mole = Mass / Molar Mass

    Mass = number of mole x molar Mass

    Mass of CO2 = 0.54 x 44

    Mass of CO2 = 23.76g
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