Ask Question
6 October, 01:54

What is the molality of an aqueous solution containing FeCl3 (MM = 162.2 g/mol) with a mole fraction of FeCl3 of 0.15?

+4
Answers (1)
  1. 6 October, 05:07
    0
    10 m

    Explanation:

    The mole fraction of FeCl₃ of 0.15, that is, per mole of solution, there are 0.15 moles of FeCl₃ and 1 - 0.15 = 0.85 moles of water.

    The molar mass of water is 18.02 g/mol. The mass corresponding to 0.85 moles is:

    0.85 mol * 18.02 g/mol = 15 g = 0.015 kg

    The molality of FeCl₃ is:

    m = moles of solute / kilogram of solvent

    m = 0.15 mol / 0.015 kg

    m = 10 m
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the molality of an aqueous solution containing FeCl3 (MM = 162.2 g/mol) with a mole fraction of FeCl3 of 0.15? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers