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A gas obeys the ideal-gas equation of state P V = N k T, where N = n NA is the number of molecules in the volume V at pressure P and temperature T and n is the number of gm-moles of the gas. Calculate the volume occupied by 1 gm·mole of the gas at atmospheric pressure and a temperature of 313.7 K. Avogadro's constant is 6.02214 * 1023 mol-1, Boltzmann's constant is 1.38065 * 10-23 N · m/K, and 1 atm = 1.013 * 105 N/m2. Answer in units of L.

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  1. Today, 02:24
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    The volume occupied is 25.7 L

    Explanation:

    Let's replace all the data in the formula

    P. V = N. k. T

    N = nNA

    1 gm. mole. 6.02x10²³

    k = Boltzmann's contant

    T = T° in K

    1 atm = 1.013 * 10⁵ N/m2

    1.013 * 10⁵ N/m2. Volume = 6.02x10²³. 1.38065 * 10⁻²³ N · m/K. 313.7K

    Volume = (6.02x10²³. 1.38065 * 10⁻²³ N · m/K. 313.7K) / 1.013 * 10⁵ m2/N

    Volume = 2607.32 N. m / 1.013 * 10⁵ m2/N = 0.0257 m³

    1 dm³ = 1 L

    1m³ = 1000 dm³

    25.7 L
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