At elevated temperatures ammonium carbamate, NH2COONH4, is in equilibrium with NH3 and CO2 according to the equation:

NH2COONH4 (s) - -> 2 NH3 (g) + CO2 (g)

What is the equilibrium expression for this reaction?

K = 2[NH3] [CO2] / [NH2COONH4]

K = 2[NH3] [CO2]

K = [NH3]^2 [CO2]

K = [NH3]^2 [CO2] / [NH2COONH4]

Question

Chemistry

Gauge Roy

8 February, 02:19

At elevated temperatures ammonium carbamate, NH2COONH4, is in equilibrium with NH3 and CO2 according to the equation:

NH2COONH4 (s) - -> 2 NH3 (g) + CO2 (g)

What is the equilibrium expression for this reaction?

K = 2[NH3] [CO2] / [NH2COONH4]

K = 2[NH3] [CO2]

K = [NH3]^2 [CO2]

K = [NH3]^2 [CO2] / [NH2COONH4]

+4

Answers (1)

Know the Answer?

Jocelynn Estrada · Answer 1

D

Explanation:

To get the equilibrium expression for a reaction, we simply write an equation for the equilibrium constant K. We place the product of the concentrations of the products in square bracket divided by the concentrations of the reactants. We raise the power of the concentration to the coefficient indicating the number of moles of the reactant or product having more than one mole. In this question particularly, the equilibrium expression is:

K = [NH3]^2[CO2]/[NH2COONH4]