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28 March, 15:23

You make two dilutions. You take 83.52 mL of the stock solution and dilute to 500.0 mL to make Solution #1. You then add 52.27 mL of Solution #1 to 46.77 mL of water to make Solution #2. What is the concentration of the Solution #1 in terms of molarity?

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  1. 28 March, 17:08
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    The answer to the question is;

    The concentration of the Solution #1 in terms of molarity is

    0.16704X moles/litre.

    Explanation:

    Let the concentration of the stock solution be X moles/liter

    Therefore, 83.52 ml of the stock solution contains

    83.52 * (X/1000) moles

    Dilution of 83.52 ml of X to 500 ml gives solution 1 with a concentration of

    500 ml of solution 1 contains 83.52 * (X/1000) moles

    Therefore 1000 ml or 1 litre contains 2*83.52 * (X/1000) moles = 0.16704X moles/litre

    The molarity of solution 1 is 0.16704X moles/litre.
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