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26 May, 08:43

How many grams of Na 2 CO 3 are present in 21.0 mL of a solution that is 36.0 % Na 2 CO 3 by mass? The density of the solution is 1.12 g / mL.

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  1. 26 May, 10:43
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    The answer to your question is 8.46 g of Na₂SO₄

    Explanation:

    Data

    mass of Na₂CO₃ = ?

    volume = 21 ml

    percent by mass = 36%

    density = 1.12 g/ml

    Process

    1. - Calculate the mass of the solution

    density = mass / volume

    solve for mass

    mass = density x volume

    mass = 1.12 x 21

    mass = 23.52 g

    2. - Calculate the mass of Na₂CO₃

    Percent by mass = (mass of Na₂SO₄ / mass of solution) x 100

    Solve for mass of Na₂SO₄

    mass of Na₂SO₄ = Percent by mass x mass of solution/100

    mass of Na₂SO₄ = 36 x 23.52/100

    mass of Na₂SO₄ = 8.46 g
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