1. How many moles of AgNO3 are in 15.0 g?

Answer: 0.088 moles

Explanation:

Parameters given:

Mass of AgNO3 = 15.0g

To know the number of moles, given such parameter, we need to find and use the molecuar weight formular. The molecuar weight is mass per mole

Molecular weight = mass / mole

Molecular weight of AgNO3

Ag + N + 03

107.8682 + 14.0067 + 15.9994 (3)

(Note, that the weight of each compounds are standards)

= 169.8731g/mole

Using our molecular weight formular

Moles of AgNO3 in 15.0g

Let Number of Moles be represented as Y

169.8731g/mole = 15.0g / Y

Therefore,

Y = 169.8731 / 15.0g

Y = 0.088 moles

No of Moles of AgNo3 in 15.0g = 0.088moles