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24 December, 18:10

A solution is prepared by mixing 50.0 mL of ethanol with 300.0 mL of water. What is the volume percent of ethanol in this solution? Assume volumes are additive.

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  1. 24 December, 21:44
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    The answer to your question is 14.3 %

    Explanation:

    Data

    volume of ethanol = 50 ml

    volume of water = 300 ml

    volume percent = ?

    Formula

    Percent by volume = (volume of solute/volume of solution) x 100

    Volume of solute = 50 ml

    volume of solution = 300 + 50 = 350

    Substitution

    Percent by volume = (50/350) x 100

    Simplification and result

    Percent by volume = 14.3 %
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