What is the molarity of a solution containing 2 moles of HCl (hydrochloric acid) in 3 liters of water?

Answer:0.67molL-1

Explanation:

From n = CV

n=2 moles, v=3L

Molarity is given in moles per litre

C = n/v = 2/3=0.67molL-1

The molarity of this solution of hydrochloric acid is 0.67 M

Explanation:

Step 1: Data given

Number of moles HCl = 2

Volume = 3.0 L

Molarity = mol / volume

Step 2: Calculate molarity of the solution

Molarity = moles / volume

Molarity HCl solution = 2.0 moles / 3.0 L

Molarity HCl solution = 0.67 M

The molarity of this solution of hydrochloric acid is 0.67 M