Ask Question
13 April, 07:24

Consider a hypothetical experiment in which the left beaker contains 4 mM NaCl, 9 mM glucose and 10 mM albumin. The right beaker contains 10 mM NaCl, 10 mM glucose and 40 mM albumin. The dialysis membrane is permeable to all substances except albumin. In which direction will glucose move?

+3
Answers (1)
  1. 13 April, 09:12
    0
    to the left beaker

    Explanation:

    In the system above, we have two beakers containing different concentrations of glucose. In addition, the two beakers are separated by a permeable membrane which can allow the movement of glucose from one beaker to another. In order to attain equilibrium conditions, there will be a movement of glucose from the beaker with high glucose concentration (right beaker) to the beaker with low glucose concentration (left beaker).
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Consider a hypothetical experiment in which the left beaker contains 4 mM NaCl, 9 mM glucose and 10 mM albumin. The right beaker contains ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers