If 22.99 g of sodium and 35.45 g of chlorine fully react, how much sodium chloride forms?

The answer to your question is: HCl = 58.44 g

Explanation:

To solve this problem, we must remember the law of conservation of mass that says that, matter cannot be created or destroyed, only changes its form.

That means that, the mass of the reactants must be equal to the mass of the products.

Process

Sodium (Na) + Chlorine (Cl) ⇒ Sodium chloride (HCl)

22.99 g 35.45 g x

22.99 + 35.45 = HCl

HCl = 58.44 g