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5 November, 08:07

A 25.0 g bold made of an alloy absorbed 250 J of heat as its temperature changed from 25.0 °C to 78.0 °C. What is the specific heat of the alloy?

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  1. 5 November, 10:25
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    Specific heat of alloy = 0.2 j / g.°C

    Explanation:

    Specific heat capacity:

    It is the amount of heat required to raise the temperature of one gram of substance by one degree.

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    Given dа ta:

    Mass of bold = 25 g

    Heat absorbed = 250 J

    Initial Temperature = 25°C

    Final temperature = 78°C

    Specific heat of alloy = ?

    Solution:

    Change in temperature:

    ΔT = 78°C - 25°C

    ΔT = 53°C

    Now we will put the values in formula.

    Q = m. c. ΔT

    250 j = 25 g * c * 53°C

    250 j = 1325 g.°C * c

    250 j / 1325 g.°C = c

    c = 0.2 j / g.°C
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