3) How many L of gas is equal to 89.3 moles at STP?

The correct answer is 1999 l

Explanation:

We use the formula P V = nRT. The normal conditions of temperature and pressure are 273K and 1 atm, we use the gas constant = 0, 082 l atm / K mol:

1 atm x V = 0, 082 l atm / K mol x 89, 3 mol x 273 K

V = 0, 082 l atm / K mol x 89, 3 mol x 273 K / 1 atm

V = 1999, 06 l