Ask Question
26 February, 23:56

Find q when 22.0g of water is heated from 17.0 degrees Celsius to 100 degrees Celsius

+2
Answers (1)
  1. 27 February, 03:21
    0
    When 22.0 g of water is heated from 17 °C to 100 °C what amount of heat absorbed?

    When 22.0 g of water is heated from 17 °C to 100 °C water absorbed 7643.64 j heat.

    Explanation:

    Specific heat capacity:

    It is the amount of heat required to raise the temperature of one gram of substance by one degree.

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    Given dа ta:

    Mass of water = 22.0 g

    Initial temperature = 17°C

    Final temperature = 100°C

    Solution:

    ΔT = T₂ - T₁

    ΔT = 100°C - 17 °C = 83°C

    Q = m. c. ΔT

    Q = 22 g * 4.186 j/g °C * 83 °C

    Q = 7643.64 j

    It means water require more heat which is 7643.64 j to increase its temperature from 17 °C to 100 °C.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Find q when 22.0g of water is heated from 17.0 degrees Celsius to 100 degrees Celsius ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers