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29 September, 14:47

A real gas is in a regime in which it is accurately described by the ideal gas equation of state. 27.1 g of the gas occupies 50.0 L at a pressure of 0.500 atm and a temperature of 449 K. Identify the gas.

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  1. 29 September, 17:04
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    Argon

    Explanation:

    Given data

    Mass (m) : 27.1 g Volume (V) : 50.0 L Pressure (P) : 0.500 atm Temperature (T) : 449 K

    We can find the molar mass (M) of the gas using the ideal gas equation.

    P * V = n * R * T

    P * V = m/M * R * T

    M = m * R * T/P * V

    M = 27.1 g * (0.08206 atm. L/mol. K) * 449 K / 0.500 atm * 50.0 L

    M = 39.9 g/mol

    If the gas is monoatomic, the one with a molar mass of 39.9 g/mol is argon.
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