A real gas is in a regime in which it is accurately described by the ideal gas equation of state. 27.1 g of the gas occupies 50.0 L at a pressure of 0.500 atm and a temperature of 449 K. Identify the gas.

Argon

Explanation:

Given data

Mass (m) : 27.1 g Volume (V) : 50.0 L Pressure (P) : 0.500 atm Temperature (T) : 449 K

We can find the molar mass (M) of the gas using the ideal gas equation.

P * V = n * R * T

P * V = m/M * R * T

M = m * R * T/P * V

M = 27.1 g * (0.08206 atm. L/mol. K) * 449 K / 0.500 atm * 50.0 L

M = 39.9 g/mol

If the gas is monoatomic, the one with a molar mass of 39.9 g/mol is argon.