Ask Question
21 August, 15:09

A driver blows 0.75 - L air bubble 10 m under water. As it rises to the surface, the pressure goes from 2.25 atm to 1.03 atm. What will be the volume of air in the bubble at the surface?

+3
Answers (1)
  1. 21 August, 15:54
    0
    1.64 L

    Explanation:

    P₁V₁ = P₂V₂

    P₁ = 2.25 atm

    V₁ = 0.75 L

    P₂ = 1.03 atm

    V₂ = ?

    (2.25 atm) (0.75 L) = (1.03 atm) V₂

    [ (2.25 atm) (0.75 L) ] / (1.03 atm) = V₂

    V₂ = 1.64 L
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A driver blows 0.75 - L air bubble 10 m under water. As it rises to the surface, the pressure goes from 2.25 atm to 1.03 atm. What will be ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers