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3 April, 00:13

A student reacted NiS2 (MM = 122.83 g/mol) with O2 (MM=32.00 g/mol) to make SO2 (MM=64.07 g/mol) according to this balanced equation

2NiS2+5O2=2NiO+4SO2

If the actual amount of SO2 made were (4.3090x10^2) g ehen the theoretical yield was (8.78x10^2) g what was the percent yield?

Enter in scientific notation

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Answers (1)
  1. 3 April, 02:24
    0
    Percentage yield = 0.49 * 10² %

    Explanation:

    Given dа ta:

    Actual yield of SO₂ = 4.309 * 10² g

    Theoretical yield of SO₂ = 8.78 * 10² g

    Percentage yield = ?

    Solution:

    Chemical equation:

    2NiS₂ + 5O₂ → 2NiO + 4SO₂

    Percentage yield:

    Percentage yield = actual yield / theoretical yield * 100

    Percentage yield = 4.309 * 10² g / 8.78 * 10² g * 100

    Percentage yield = 0.491 * 100

    Percentage yield = 49.1%

    In scientific notation:

    Percentage yield = 0.49 * 10² %
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