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4 January, 12:39

A student reacted NiS2 (MM = 122.83 g/mol) with O2 (MM=32.00 g/mol) to make SO2 (MM=64.07 g/mol) according to this balanced equation

2NiS2+5O2=2NiO+4SO2

If (1.50x10^2) g of NiS2 were reacted with (2.420x10^2) g of O2 what would be the theoretical yield of SO2

Enter in scientific notation

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  1. 4 January, 14:35
    0
    Theoretical yield of SO₂ is 1.56 * 10² g

    Explanation:

    Given dа ta:

    Mass of NiS₂ = 1.50 * 10² g

    Mass of O₂ = 2.420 * 10² g

    Theoretical yield of SO₂ = ?

    Solution:

    Chemical equation:

    2NiS₂ + 5O₂ → 2NiO + 4SO₂

    Moles of NiS₂:

    Number of moles = mass / molar mass

    Number of moles = 1.50 * 10² g / 122.83 g/mol

    Number of moles = 1.22 mol

    Moles of O₂:

    Number of moles = mass / molar mass

    Number of moles = 2.420 * 10² g / 32 g/mol

    Number of moles = 7.56 mol

    Now we compare the moles of SO₂ with NiS₂ and O₂.

    NiS₂ : SO₂

    2 : 4

    1.22 : 4/2*1.22 = 2.44

    O₂ : SO₂

    5 : 4

    7.56 : 4/5*7.56 = 6.05

    Moles of SO₂ produced by NiS₂ are less it will limiting reactant.

    Mass of SO₂ = moles * molar mass

    Mass of SO₂ = 2.44 mol * 64.07 g/mol

    Mass of SO₂ = 156.33 g

    So theoretical yield of SO₂ is 1.56 * 10² g
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