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28 November, 23:20

Calculate the amount of CuSO4•5H2O required to make 25 mL of a 0.45 M solution of CuSO4.

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  1. 29 November, 02:17
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    Mass = 1.76 g

    Explanation:

    Given dа ta:

    Volume of solution = 25 mL

    Molarity = 0.45 M

    Amount of CuSO₄.5H₂O = ?

    Solution:

    Molarity = number of moles / volume in litter

    Number of moles = Molarity * Volume in L

    Number of moles = 0.45 M * 0.025 L

    Number of moles = 0.011 mol

    Mass of f CuSO₄.5H₂O:

    Mass = Number of moles * molar mass

    Mass = 0.011 mol * 159.6 g/mol

    Mass = 1.76 g
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