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23 February, 18:57

A balloon is filled with 35.0 L of helium in the morning when the temperature is 303 degrees kelvin. By 3:00 p. m., the temperature has risen to 333 degrees kelvin. What is the new volume of the balloon?

2882 L

38.5 L

31.8 L

65.0 L

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Answers (1)
  1. 23 February, 20:13
    0
    38.5 L

    Explanation:

    For this question, we can use

    V1/T1=V2/T2

    where

    V1 (initial volume) = 35 L

    T1 (initial temperature in Kelvin) = 303 K

    V2 (final volume) = ?

    T2 (final temperature in Kelvin) = 333K

    Since we are trying to find the final volume, we can rearrange the equation to say

    V2 = (V1/T1) * T2

    V2 = (35/303) * 333

    V2 = 38.5 L
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