Ask Question
18 October, 00:42

29.5 g of mercury is heated from 32°C to 161°C, and absorbs 499.2 joules of heat in the process. Calculate the specific heat capacity of mercury (in Jg°C).

+2
Answers (1)
  1. 18 October, 01:36
    0
    c = 0.13 j / g.°C

    Explanation:

    Given dа ta:

    Mass of mercury = 29.5 g

    Initial temperature = 32°C

    Final temperature = 161°C

    Heat absorbed = 499.2 j

    Solution:

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    Q = m. c. ΔT

    ΔT = T2 - T1

    ΔT = 161°C - 32°C

    ΔT = 129 °C

    Q = m. c. ΔT

    c = Q / m. ΔT

    c = 499.2 j / 29.5 g. 129 °C

    c = 499.2 j / 3805.5 g. °C

    c = 0.13 j / g.°C
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “29.5 g of mercury is heated from 32°C to 161°C, and absorbs 499.2 joules of heat in the process. Calculate the specific heat capacity of ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers