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14 June, 00:12

What NaCl NaCl concentration results when 249 mL 249 mL of a 0.850 M 0.850 M NaCl NaCl solution is mixed with 667 mL 667 mL of a 0.420 M 0.420 M NaCl NaCl solution?

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  1. 14 June, 03:51
    0
    The answer to your question is 0.54M

    Explanation:

    Data

    Final concentration = ?

    Concentration 1 = 0.850 M

    Volume 1 = 249 ml = 0.249 l

    Concentration 2 = 0.420 M

    Volume 2 = 0.667 M

    Process

    1. - Calculate the number of moles in both solutions

    Number of moles 1 = Molarity 1 x Volume 1

    = 0.850 x 0.249

    = 0.212

    Number of moles 2 = Molarity 2 x Volume 2

    = 0.420 x 0.667

    = 0.280

    Total number of moles = 0.212 + 0.280

    = 0.492

    2.-Calculate the final volume

    Final volume = Volume 1 + Volume 2

    Final volume = 0.249 + 0.667

    = 0.916 l

    3. - Calculate Molarity

    Molarity = 0.492 / 0.916

    Molarity = 0.54
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