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20 March, 06:04

29.52 mg of a non-ionizing biological macromolecule is dissolved in 10.00 mL of water with no volume change. The osmotic pressure of the solution at 23.5 oC is determined to be 1.44 x 10 - 3 atm. Determine the molar mass of the macromolecule.

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  1. 20 March, 08:06
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    49902.4 g/mol.

    Explanation:

    Using ideal gas equation,

    PV = nRT

    Where,

    P = pressure

    = 0.00144 atm

    V = volume

    = 0.01 l

    T = absolute temperature

    = 273 + 23.5

    = 296.5 K

    R = gas constant

    = 0.0821 atm. l/K. mol

    n = number of moles

    n = (0.00144 * 0.01) / 0.0821 * 296.5

    = 5.92 x 10^-7 mol.

    Molar mass = mass/number of moles

    = 0.02952/5.92 x 10^-7

    = 49902.4 g/mol.
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